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x^2-44x-483=0
a = 1; b = -44; c = -483;
Δ = b2-4ac
Δ = -442-4·1·(-483)
Δ = 3868
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3868}=\sqrt{4*967}=\sqrt{4}*\sqrt{967}=2\sqrt{967}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-2\sqrt{967}}{2*1}=\frac{44-2\sqrt{967}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+2\sqrt{967}}{2*1}=\frac{44+2\sqrt{967}}{2} $
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